00:01
Hello students, in this question we have to find out the change in ph.
00:04
If the concentration of the hydronium ion changes by the given factor.
00:09
The first factor given here is the 1000.
00:12
That is the concentration of the hydronium ion increased 1000 times.
00:17
We know that the ph of the solution is given by minus log of concentration of hydronium ion.
00:26
Let it be ph number 1.
00:28
Now we are going to calculate our new ph that is ph 2 which is given by minus log of the concentration of hydronium ion is 1000 into concentration of hydronium ion.
00:40
We are expanding this that is minus log of 1000 minus log of hydronium ion.
00:50
So this will be equal to ph 1 and this will be equal to 3 plus ph 1 will be equal to ph 2.
01:03
On rearranging this we will get the change in ph, delta ph will be equal to 3.
01:10
This is the answer to the first question.
01:13
This is the second factor given in the question.
01:16
So we are substituting this in the ph 3 formula that is minus log of 1 into 10 to the power 5 into concentration of the hydronium ion...