00:01
So for this question, you're asked to find the work done by the helium gas and also the change in internal pressure.
00:08
So first we're going to calculate the work because we're going to need that number in order to calculate the internal energy.
00:16
So in order to calculate the work, we are going to use the equation where work equals a negative pressure times the change in volume.
00:27
We are told that the pressure is held constant at 0 .91 atmospheres and that the gas expands from 6 .21 liters to 20 .4 liters.
00:39
So i have them labeled as the initial volume vi and the final volume bf.
00:46
So first we'll calculate work.
00:48
So work is going to equal negative times our pressure of 0 .981 atmospheres.
00:59
Times our change in volume, which is the final volume minus the initial volume.
01:05
So we'll say 20 .4 liters minus 6 .21 liters.
01:13
And then just type that into your calculator and you should get a negative number, right, because it's negative here.
01:24
And you should get negative 13 .92 liters per atoms.
01:30
However, we're asked to find the work done in joules.
01:33
So we have to convert liters at atoms to jewels.
01:36
So we'll just do a simple unit conversion.
01:39
So we have negative 13 .92 liters per atoms.
01:45
So we'll take that times 101 .3 joules because there's 101 .3 joules for every one liter times atom.
01:54
So we'll see our unit conversion.
01:56
The units will cancel.
01:58
So we'll be left for the joules.
01:59
So type that in your calculator, negative 13 .92 times 101 .3...