Question

What is the concentration of a sodium hydroxide solution if 0.2033 g of potassium hydrogen phthalate (KHP- MW 204.22 g/mol) requires 10.40 mL of NaOH solution to reach the phenolphthalein end point? Answer with three decimal places.

          What is the concentration of a sodium hydroxide solution if
0.2033 g of potassium hydrogen phthalate (KHP- MW 204.22 g/mol)
requires 10.40 mL of NaOH
solution to reach the phenolphthalein end point?
Answer  with three decimal places.
        
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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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What is the concentration of a sodium hydroxide solution if 0.2033 g of potassium hydrogen phthalate (KHP- MW 204.22 g/mol) requires 10.40 mL of NaOH solution to reach the phenolphthalein end point? Answer with three decimal places.
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The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium hydrogen phthalate (abbreviated as KHP). KHP is an acid with one acidic hydrogen and a molar mass of 204.22 g/ mol. In the titration, 34.67 mL of the sodium hydroxide solution was required to react with 0.1082 g KHP. Calculate the molarity of the sodium hydroxide.

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The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium hydrogen phthalate (abbreviated as KHP). KHP is an acid with one acidic hydrogen and a molar mass of 204.22 g/ mol. In the titration, 34.67 mL of the sodium hydroxide solution was required to react with 0.1082 g KHP. Calculate the molarity of the sodium hydroxide.

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The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium hydrogen phthalate (abbreviated as KHP). KHP is an acid with one acidic hydrogen and a molar mass of 204.22 g/ mol. In the titration, 34.67 mL of the sodium hydroxide solution was required to react with 0.1082 g KHP. Calculate the molarity of the sodium hydroxide.

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Transcript

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0:00 Good day.
00:01 In this question we are asked to solve for the concentration of sodium hydroxide.
00:06 So first we need to write the neutralization equation between the potassium hydrogen calate and an aoh.
00:17 So this will yield to the potassium sodium calate plus h2o.
00:32 So this is the balance equation unruly.
00:35 Next we solve for the mole of n .a .o .h.
00:43 By stoch chemistry, so from 0 .23 grams of kh times one mole of khp is 204 .2 grams khp.
01:01 Times one mole of n .a .o .h is one mole of p .h...
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