00:01
Hello, here we have to solve the following assignment.
00:02
In question one, we have to calculate concentration of each ion in 0 .25 molar solution of calcium nitrate.
00:12
Let's first calculate concentration of calcium 2 plus.
00:15
That is 0 .25 molar.
00:18
Meanwhile, concentration of a nitrate is twice concentration of calcium, which is half a molar.
00:28
Now, let's move on to question two.
00:31
Here we have to calculate mass which is needed to prepare 0 .15 liters of half a molar sodium sulfate.
00:42
So to solve this problem, to find this mass, we have to multiply the volume by concentration and by molar mass of sodium sulfate.
00:59
So let's find this molar mass.
01:08
This molar mass is 142 gram per mole.
01:16
Now we can complete the calculation and calculate the concentration...