What is the density of atoms/nm² on the (110) plane of a zinc blende lattice with lattice spacing 0.546 nm? Three significant digits, fixed-point notation.
Added by Jose Carlos W.
Step 1
Given lattice spacing a = 0.546 nm, for the (110) plane of a zinc blende lattice, the lattice constant is calculated as: r = a / (2 * sqrt(2)) r = 0.546 / (2 * sqrt(2)) r ≈ 0.193 nm Show more…
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