00:01
According to the question, we have to find out the empirical formula for a compound containing sulfur, oxygen and chlorine in the percentage, 27 % for sulfur and for oxygen, 13 .4 percentage and for chlorine, 59 .6 percentage.
00:19
Let us consider that the compound be 100 gram, then mass of sulfur, oxygen and chlorine respectively would be 27 gram, sulfur, 14 .4 gram of oxygen and 59 .6 gram for chlorine.
00:36
Now let us write down the molar masses of this element for sulfur.
00:42
Molar mass would be 32 gram per mole.
00:46
For oxygen, 16 gram per mole and for chlorine it would be 35 .5 gram per mole.
00:52
Now we will calculate the moles of sulfur, oxygen and chlorine in the compound.
01:00
For sulfur and for this we will divide the mass with molar mass 27 divided by 32 for sulfur will give 0 .8437 and for oxygen 13 .4 divided by 16 will give 0 .8375 will give 0 .8375 and for chlorine 59 .6 divided by 35 .5 will give 1 .6788.
01:29
Now, now, to find out the whole number, we will divide the lowest mole with all three of them...