What is the equation of the circle pictured? $(x-8)^2 + (y-8)^2 = 64$ $(x-8)^2 + (y-8)^2 = 0$ $x^2 + y^2 = 64$ $x^2 + y^2 = 8$
Added by Catalina A.
Close
Step 1
From the given equation (I - 8)^2 + (y + 8)^2 = 64, we can see that the center of the circle is at (8, -8) and the radius is 8. Show more…
Show all steps
Your feedback will help us improve your experience
Tanya Chase and 52 other Geometry educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Write the center-radius form of the circle with the given equation. Give the center and radius, and graph the circle. $$ x^{2}+y^{2}+8 x+2 y-8=0 $$
Nonlinear Functions, Conic Sections, and Nonlinear Systems
Circles Revisited and Ellipses
Sketch the circle. Identify its center and radius. $$x^{2}+8 x+y^{2}+2 y+8=0$$
Conics and Parametric Equations
Circles and Parabolas
Determine (a) the radius and (b) the co-ordinates of the centre of the circle given by the equation: $x^{2}+y^{2}+8 x-2 y+8=0$.
Recommended Textbooks
Geometry A Common Core Curriculum
Geometry
Watch the video solution with this free unlock.
EMAIL
PASSWORD