00:01
Here in this question there are many parts so i will solve all of them one by one so the first part is what is the equivalent resistance of three registers connected in series 1k om 2k home and 3k home 1k home 2k home and 3k oom so r1 r2 r3 r3 2 1 oom oom and oom so our equivalent in case of series connection is nothing but r1 plus r2 plus r3.
00:35
So we just need to add them simply.
00:38
So it would be 6 oms.
00:39
So our equivalent would be 6 oms.
00:41
In the second part, it says that what is the equivalent resistance for 3 registers connected in series if their respective voltage drop is 2, 3 and 5 volts.
00:53
So voltage drop is 2 volt, 3 volt and 5 volt.
01:00
And current flowing is 0 .2 ampires.
01:07
So v is equal to i into r.
01:13
Okay.
01:14
So r would be v over i.
01:21
So r here would be 20 oms.
01:24
Here it would be 3 by 0 .2 that means 15 oms.
01:33
And here it would be 5 over 0 .2 that means 25 oms.
01:41
Here let me check.
01:43
Yeah, it would be 10, not 20.
01:44
So that's it in the second question the equivalent resistance would be just simply summation of all this because they are connected in series so our equivalent would be 25 plus 15 that is 40 plus 10 50 or else we can also calculate that what is the total potential difference that is 5 plus 2 that means 10 volt and divided by the current that is 0 .2 here also we can calculate our equivalent would be equal to 50 so these are the two methods.
02:19
Next.
02:20
What is next? let me see.
02:26
A 650 om and 2 ,200 registers are connected in a series with a 20 volt battery...