What is the freezing point of an aqueous 1.58 molal NaCl solution? (Kf = 1.86°C/m) A) -2.94°C B) 2.94°C C) -5.88°C D) 5.88°C E) 0.00°C
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We can use the formula: ΔTf = Kf * molality where ΔTf is the freezing point depression, Kf is the cryoscopic constant (1.86 °C/m for water), and molality is 1.58 molal. ΔTf = 1.86 °C/m * 1.58 m = 2.9396 °C Show more…
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