00:01
So here what we need to calculate is we need to calculate the frequency.
00:05
We need to calculate frequency and the energy.
00:09
And we have the wavelength.
00:10
And we have the wavelength.
00:12
For the molybedenum we have is 0 .71 angstrom.
00:17
And for the copper, what we have is 1 .54 angstrom.
00:21
Okay.
00:22
So when we have the, then we need to calculate frequency, but we are given with the wavelength, that is the lambda value, right? so we have a relation that is mu is equal to c upon lambda here this mu is our frequency right c is speed of light c is our speed of light or we can say the velocity of light okay and here lambda is our wavelength here lambda is our wave length right so speed of light is fixed that is c value is our 3 into 10 x per 8 meters per second right so now first what we will do is we will calculate the frequency so here what we have is m o here we have is this now here we have c upon lambda right so now we have three into 10 raised per 8 meters per second right now upon what we have 0 .71 here we have 0 .71 into 10 r.
01:24
10.
01:26
Why 10 risper minus 10 meters? because 1 angstrom is equal to 10 risper minus 10 meters.
01:33
So from here we got the frequency value for moly bit an m.
01:38
That is 4 .23 into 10 risper 8 per second.
01:43
Okay, that is per second.
01:47
Now, if we calculate for the copper, so we have is this.
01:52
That is again c upon lambda.
01:55
That is 3 into 10 xper 8 meter per second...