What is the function based of this information the zeros of...

what is the function based of this information? The zero(s) of f(x)occur at: x= -3,3, The vertical asymptote(s) of f ( x ) occur at: x = -4,0, The zero(s) of n ( x ) : x = -3,3, The zero(s) of d ( x ) : x = -4,0, The zero(s) of n ( x ) of even multiplicity: x = -3, The zero(s) of d ( x ) of even multiplicity: x = 0, The horizontal asymptote of f ( x ) : y = -1

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00:01 Problem here, and i see that we've got the majority of the problem correct with the zeros of the function, the asymptotes, and the zeros of the numerator, denominator, etc.

00:11 The point i'm seeing there's an issue is is the zeros of the denominator, whether they, which one has an even multiplicity.

00:22 Well, let's just review the zeros of the denominator are negative five and one.

00:27 So i see at negative five we have that vertical asymptote, and at one we're going to have that vertical asymptote.

00:33 Because they're shooting off in opposite directions, this one's going to have an odd multiplicity.

00:39 Since these are shooting up in the same direction, that's going to be an even multiplicity.

00:44 I see that you put one in there as an answer, and that is the correct answer.

00:48 So i'm not sure why that's being counted wrong on your particular problem.

00:53 Now because of that, that's probably why you got the function wrong.

00:56 Let's look and see what our function should be.

00:59 We have our denominator is zeros are going to be at negative five, which means we're going to have x plus five, and we're going to have it at one.

01:08 So it'd be x minus one.

01:10 That should be an even multiplicity, so we're going to put that at two.

01:14 And then the numerator, we have the zeros at negative three and four...

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