00:01
Hello students here we have in the question that to calculate the hybridization of the ccl4 molecule.
00:08
So we have to calculate or we have to say what is the hybridization of ccl4.
00:16
Okay so what is hybridization of ccl4? so in this we have ccl4 the central, the centralization of ccl4.
00:32
Central atom is carbon.
00:34
So what is the electron configuration? outer electronic configuration of carbon is 1h2, 2s2 and 2p2 is an electronic configuration.
00:49
So here are two electrons and here two electrons.
00:52
It is in ground state.
00:54
Okay? so it is ground state.
00:58
If it is in excited state, it will form 2s1 and 2 .s1.
01:03
P3 then we have one electron in s and three electrons in p okay so we have chlorine atoms four chlorine items so for chlorine there are three loan paid of electrons and one unpaired electrons if it takes one electron it will get stable ionic or stable atomic configuration so that is noble gas configuration.
01:35
So that's why what it will do, it will shape this electron to this carbon and make one covalent bond this one...