Question

What is the intensity (in nW/m^2 or 10^-9 W/m^2) of a sound that is 4.9 dB higher than a 6.9*10^-9 W/m^2 sound? Enter an integer.

          What is the intensity (in nW/m^2 or 10^-9 W/m^2) of a sound that is 4.9 dB higher than a 6.9*10^-9 W/m^2 sound? Enter an integer.
        

Added by Brittany B.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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What is the intensity (in nW/m^2 or 10^-9 W/m^2) of a sound that is 4.9 dB higher than a 6.9*10^-9 W/m^2 sound? Enter an integer.
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Transcript

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00:01 Hi guys, now in this problem, the decibel level of sound is about 78 .1 decibel.
00:05 Basically, the power is, the power of sound is measured in a what, decibel form, decibel unit p is equal to, this is 7 .8 .1 decibel.
00:18 Now the formula for power of sound is given as 10 log of i divide by i.
00:25 Not what is i not a i not is a i not is about a reference intensity that is what 10 times 10 to the power minus 12 watt per meter square so in order to find out what is the intensity of the sound i need to substitute all this value this is 7 8 .1 is equal to this is 10 times log of i divide by 10 to the power minus 12 so here i can say that let me divide this number so i can say that log of i divide by i0 sorry i not let me write an i not not writing 10 to 1 minus because it it's complex to writing 10 to my star so i'm writing just i not this is 7 .81 now as we know that log of x is equal to y then i can say that x is equal to 10 to the power y if there is no information about the base of logarithmic we generally take basis but 10 so i can say that i is equal to i not times and this is 10 to the power that will be what 10 to the bar 7 .81 okay so i is equal to what i is equal to you can say 10 to the power minus 12 so i can say a 10 to per minus 12 plus 7 .81 so 7 .81 minus 12 is what minus 4 .19 so i is equal to what i is equal to 10 to the power minus 4...
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