2. What is the IUPAC name of the compound on the right? A)...

2. What is the IUPAC name of the compound on the right? A) 3,4-dimethyl-1-buten-4-ol B) 3-methyl-1-penten-5-ol C) 1,2-dimethyl-3-buten-1-ol D) 3-methyl-4-penten-2-ol E) 3-vinyl-2-butanol 3. What is the IUPAC name of the compound on the right? A) (R)-2-methyl-4-pentanol B) (S)-2-methyl-4-pentanol C) (R)-4-methyl-2-pentanol D) (S)-4-methyl-2-pentanol E) 2-hydroxy-4-methylpentane 4. What is the IUPAC name of the compound on the right? A) (E)-2-methyl-3-penten-2-ol B) (Z)-2-methyl-3-penten-2-ol C) (E)-1,1-dimethyl-2-buten-1-ol D) (Z)-4,4-dimethyl-2-buten-4-ol E) (E)-4-hydroxy-4-methyl-2-pentene 5. All of the compounds below have molecular weights very close to 60 g/mol. Which one has the highest boiling point? A) (CH3)2C=O B) HO-CH2-CH2-OH C) CH3CH2CHO D) CH3CH2CH2-OH E) CH3CH2C?CH 6. All of the compounds below have molecular weights very close to 60 g/mol. Which one has the lowest boiling point? A) (CH3)2C=O B) HO-CH2-CH2-OH C) CH3CH2CHO D) CH3CH2CH2-OH E) CH3CH2C?CH 7. Which one of the following alcohols cannot be easily oxidized with Jones reagent? A) 2-methyl-1-butanol B) 3-methyl-1-butanol C) 3-methyl-2-butanol D) 2-methyl-2-butanol E) 3,3-dimethyl-1-butanol

Transcript

00:01 Hello students, let's begin with this question.

00:03 Here we have to write down the iupac name.

00:06 So firstly, select the longest carbon chain.

00:09 So this is the first carbon, second carbon, third carbon and fourth carbon.

00:15 So now its iupac name is 1 and 2 at the first and the second position there is a methyl group, 1, 2 dimethyl, then 3 butane because there is a double bond is present at third position and 1, o because this oh group is present over here.

00:36 Now in the second compound here for this, here this is the first carbon, second carbon, third, fourth and fifth carbon and if we see here this is numbered as first because this oxygen is attached.

00:54 So this is the second one, this is the third one and this is the fourth one.

00:58 So this will have the r conjugation.

01:02 So if we have to write down its name, so r, 4 methyl and methyl group is present at fourth position and pent, then here we get that 4 methyl, then 2 pentanol because this oh group is present at the second position.

01:23 Now here for the third, here if we write down the numbering here, this is the first one, second one, third, fourth and fifth.

01:36 So here this is the e, here comes this e conjugation because here is the hydrogen and here is the hydrogen because the lowest this priority groups are on the opposite sides.

01:49 So e, then 2 methyl as this methyl group is present at a second position, 3 pentane, 2 ole.

02:01 Now here in the next part, these compounds are given and we have to find out which will have the higher boiling point.

02:12 So stronger the intermolecular forces of attraction that are present in a molecule, higher is the boiling point.

02:28 So here we have to observe the hydrogen bonding.

02:33 So more is the hydrogen bonding, more is the boiling point.

02:40 Now let's see, here the first one is this acetone, it will have a boiling point of 56 degree celsius.

02:47 Next one is this ethylene glycol, it will have 197 .3 degree celsius.

02:51 Next one is this aldehyde, aldehyde have generally the lower boiling point as compared to the ketones.

02:57 Next one is the, this alcohol propanol is given 97 degree celsius and this alkyne is given which is 8 .8 degree celsius.

03:06 So here if we see, if we talk about this, this ohch2ch2oh, this will have the more hydrogen bonding, so it will have the higher boiling point.

03:24 So here the correct option is the option b.

03:29 Now here in the next part, these compounds are given and we have to find out that which will have the lower boiling point...

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