00:01
So in the given question we have to calculate the lead second ion concentration.
00:09
Now for finding its concentration in a solution, we can write that pb no3 whole twice, its moles are equal to mass multiplied by volume, which is in liter.
00:25
It will be equal to 0 .416 into 0 .397.
00:32
Which is equal to 0 .165152 moles.
00:43
Now, n .a .f moles are naf moles.
00:50
They are 0 .284 into 0 .457, which is equal to 0 .129788.
01:05
Now, solving this further, we have the reaction that p .b.
01:11
B.
01:12
No3 whole twice plus 2 moles of n .a .f.
01:19
They react to give p .b.
01:22
F2 which is in solid plus 2 moles of n .a .n .3 which is aqua solution...