00:01
The distance between the wire is given as 50 cm which will be equal to 0 .5 meter.
00:11
The current in each wire is given as 4 amber.
00:17
Now we have to find out the magnetic field at point a and point b.
00:22
The magnetic field due to a long straight current carrying wire is given as mu 0, i.
00:30
By 2 pi r the i is the current in the wire and r is the distance between distance between two wires so we finding the magnetic field at a the net magnetic field at a b net net net net will be a will be because of the wire 1 a magnetic field b1 will be in the point a and then the magnetic due to the b2 will be coming out of the point using the upper of this we get b net will be equal to b2 minus b1 substituting the values, we get b net will be equal to mu zero i divided by 2p .r2 minus mu zero i divided by 2 pi r1.
01:52
Here, the distance from the first wire to the point a is given us 0 .15 meter and the r2 will be the distance from the second wire to the point a, that will be 0 .35 meter.
02:09
So, substituting the values, we get 4 pi into 10 power minus 7, tesla meter per ampere into 4 ampere divided by 2 pi into 0 .35 meter minus 4 pi.
02:33
Into 10 power minus 7 newton sorry tesla meter per ambient into 4 ampier all divided by 2 5 into 0 .15 meter from this at point they get the net magnetic field will be equal to minus 220 .952 tesla...