What is the magnitude of the magnetic force (in N) on a charged particle (Q = 5 mC) moving with a speed of 22 km/s in the positive x direction at a point where Bx = 7.0 T, By = -4.0 T, and Bz = 3.0 T? Select one: a. 110 N b. 770 N c. 550 N d. 3850 N
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0 T By = -4.0 T Bz = 3.0 T V x B = Q * (V x B) V x B = Q * (Vx * Bx + Vy * By + Vz * Bz) V x B = 5 x 10^-3 * (22,000 * 7 + 0 * (-4) + 0 * 3) V x B = 5 x 10^-3 * (154,000) V x B = 770 N Show more…
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