00:01
In this question we have to tell the first the name of the reactant.
00:15
Second, we have to tell that whether this reaction follows marconikov's rule or anti -marconikov's rule.
00:38
The third, we have to tell that whether it is anti -syn or both and we have to tell the name of the final product formed.
01:09
Now we have the formula, we have been given the formula of the formula of the compound which is given as this.
01:35
So this is the name of the compound 1 pentine.
01:40
So this is 1 pentine.
01:42
Now the second thing we have to tell that whether it is following the marconikov's rule or it is following the anti -marconikov's rule.
01:55
So for this we have to tell that what is marconikov's rule.
02:02
So marconikov's rule is when an asymmetrical alkyene or alkyne gets with any hydrogen halide.
02:34
So what happens the hydrogen? gets to that carbon atom which is already bonded to the greatest number of hydrogens.
03:12
So we have to show the reaction mechanism of one pentine when reacted with a hydrogen halide.
03:26
So we will write the mechanism as so this is the reactant which is one pentine so it is it can be written as ch3 th2 ch2 t triple bond c h h and it is reacted with a hydrogen halide so now now what happens here, this electron pair goes to here and the bond will be break.
04:20
Now it will be written again...