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Hi.
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So in this question we have to tell what will be the major product formed when benzene reacts with one chloropentane in the presence of alcl3.
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Now you can notice this alcl3 is nothing but it is actually a lewis acid.
00:14
And usually in the presence of this which is a lewis acid and there is a benzene there is a possibility of having a friedelcraft alkylation because we have a halogen attached with this ring.
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So, what we are given with is this benzene and there we have a chloropentane, right? and in front of that comes this alcl3.
00:42
So, what happens is that this chlorine, because this is a lewis acid, is attracted towards this group.
00:50
So this chlorine will go ahead and jump on here.
00:54
So that way, what will happen is that you have this pentane group.
00:58
And you have this chlorine and this chlorine is further attached with this aluminum which is having these chlorines so now since it is having a great affinity towards here there is a partial positive charge that will be created on this carbon present here and we know that benzene ring is having a lot of electron charge density so there this benzene ring will then be liable to go ahead and attack on this carbon when that will happen, this bond can also go ahead and try to attack on the next carbon here...