00:01
For this reaction, we need a balanced chemical reaction, which is provided 2 lioh plus co2, yields li2, co3, plus h2o.
00:13
So we're going to start with 15 grams of lioh, and we're trying to figure out how much co2 will react.
00:20
So we're going to take this 15 grams of lioh.
00:25
And first things first, we're going to get rid of the grams of lioh, and this is going to be equal to one mole of lioh.
00:34
To find the mass of lioh, we're going to go to the periodic table.
00:38
Li 6 .94, oxygen is 16, hydrogen is 1 .01, so we end up with a mass of 23 .95.
00:50
The next step then is to get rid of our moles of lioh, so that's going to go on the bottom.
00:57
And our moles of co2 is going to go on top.
01:00
Whenever we have mole on top of mole, you have to look at the coefficients of our balanced chemical reaction...