00:02
Hi there.
00:03
In this question, we have a stoichiometry problem.
00:06
In a stoichiometry problem, we are given information about one of the substances in a equation, and we're trying to find out information about another substance in the equation.
00:16
Well, we are given, this is our balanced equation, and we are combusting or burning 2 .76 moles of the butane.
00:27
And we want to know the mass of co2 that's going to be produced.
00:33
So how many grams of co2 should be produced when we burn this many moles of butane? okay.
00:40
Well, in any stoichiometry problem, we need to use the mole ratio.
00:44
The mole ratio comes from the coefficients in the balanced equation.
00:50
Since we're interested in the butane and the carbon dioxide, i just want to focus on those two coefficients.
00:56
We see that it's a two to eight mole ratio.
00:59
Well, that will allow us to convert from moles of butane to moles of co2 by using that 2 to 8 mole ratio as our conversion factor.
01:10
Once we get to moles of co2, then we can convert to mass by using the molar mass of carbon dioxide.
01:18
Remember, molar mass is the mass of one mole of the substance, and we get that by adding together the masses of each element in the compound.
01:26
Okay, so it looks like we can complete this problem in two steps.
01:30
Let's go ahead and see.
01:31
Set this up, and we'll use dimensional analysis to solve it.
01:36
We're starting with 2 .76 moles of the c4h10.
01:41
So in our first step, we want to use that mole ratio.
01:45
And i want moles of c4h10 to cancel...