00:02
The mass of salute in each of three different solutions is our goal.
00:09
For a, we are looking at 3 .0 -0 liters of 2 .00 -molar, n -a -o -h.
00:26
For b, we have 3 .0 -0 liters of 0 .2 -2 -0 -0 -0.
00:36
Zero molar lithium bicarbonate.
00:42
And finally, for c, we have 25 .0 millimeters of 0 .50 molar copper 2 chloride.
01:00
For each of these, i'm going to pull open my molar mass tab, and we're going to get the molar mass tab for each of these.
01:09
And my first one will be 40 .00 grams per mole.
01:24
Lithium bicarbonate is 68 .01 grams per mole.
01:50
And finally, copper 2 chloride is 134 .45.
02:15
I'll switch colors for my pen.
02:19
And let's get to work.
02:22
We are given for our first problem 3 .00 liters of n -a -o -h.
02:32
Our first step will be to convert liters to a number of moles using our molarity.
02:45
Malarity is moles per liter.
02:54
Secondly, we will multiply by the molar mass, and the product of this will give us our mass of solute.
03:18
We'll be able to report this to three significant figures.
03:22
The answer is exactly 240, so i could report it like this, or i could report 2 .40 times 10 to the second grams.
03:35
Let me check my math...