00:01
I've written the information we need here.
00:02
What we're considering is saccharine.
00:05
I've written the chemical formula, the molar mass, and the size of our sample.
00:11
It's not very legible to 1 .40 grams.
00:17
We do some analysis.
00:20
We end up with 0 .2070 grams of sodium sulfate.
00:25
And here's what we know.
00:27
The s in barium sulfate is going to be equal to the mass of the sulfur in c7h5 n -o -3s.
00:49
So we've got a one -to -one mole ratio of these.
00:53
That makes this pretty easy.
00:55
So all we're going to do is convert grams of barium sulfate to mole using the molar mass.
01:20
Am i doing grams? i have a one -to -one mole ratio again of barium sulfate to saccharine...