Question

What is the minimum energy possessed by the particle in a box and the free particle? A. particle in a box = 0, free particle = $\hbar k$ B. prtaicle in a box = 0, free particle = 0 C. particle in a box = $\frac{h^2}{8mL^2}$, free particle = $\frac{h^2}{8mL^2}$ D. particle in a box = $\frac{h^2}{8mL^2}$, free particle = 0 Your answer is correct.

          What is the minimum energy possessed
by the particle in a box and the free
particle?
A. particle in a box = 0, free particle
= $\hbar k$
B. prtaicle in a box = 0, free particle
= 0
C. particle in a box = $\frac{h^2}{8mL^2}$, free
particle = $\frac{h^2}{8mL^2}$
D. particle in a box = $\frac{h^2}{8mL^2}$, free
particle = 0
Your answer is correct.

What is the minimum energy possessed
by the particle in a box and the free
particle?
A. particle in a box = 0, free particle
= ħ k
B. prtaicle in a box = 0, free particle
= 0
C. particle in a box = (h^2)/(8mL^2), free
particle = (h^2)/(8mL^2)
D. particle in a box = (h^2)/(8mL^2), free
particle = 0
Your answer is correct.

Added by Sally C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Timothy James

11/13/2022

Step 1

Step 1: The minimum energy of a particle in a box is given by the formula E = (n^2 * h^2) / (8mL^2), where n is the quantum number, h is the Planck constant, m is the mass of the particle, and L is the length of the box. Show more…

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What is the minimum energy possessed by the particle in a box and the free particle? A. particle in a box = 0, free particle = ℏk B. particle in a box = 0, free particle = 0 C. particle in a box = (h^2)/(8mL^2), free particle = (h^2)/(8mL^2) D. particle in a box = (h^2)/(8mL^2), free particle = 0 Your answer is correct. What is the minimum energy possessed by the particle in a box and the free particle? A. particle in a box = 0, free particle = ℏk B. particle in a box = 0, free particle = 0 C. particle in a box = (h^2)/(8mL^2), free particle = (h^2)/(8mL^2) D. particle in a box = (h^2)/(8mL^2), free particle = 0 Your answer is correct.