W = 2.4 KN L2 = 1.2 m L1 = 1.2 m L3 = 1.2 m BC is 75 mm wide x 10 mm thick strut. AD is 100 mm wide x 10 mm thick rigid bar. Typical connection at all joints. 7. What is the minimum required bolt diameter (mm) at C if the allowable bolt shear stress is 68 Mpa. 8. Determine the stress (Mpa) in strut BC. 9. Calculate the bolt stress (Mpa) at A if its diameter is 20 mm.
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For the system shown in Figure (1), the bolt in C is subjected to a single shear and all other bolts are double shear. The diameter of bolt at C is 15 mm, diameter of bolt at D is 10mm and diameter of bolt A is 20mm. The allowable shear stress of bolt C is 200 MPa, allowable shear stress of bolt D is 150 MPa and allowable shear stress of bolt A is 100 .MPa If the diameter of bars AB, BD and BC is 25 mm and allowable normal stress is 125 MPa determine the safe value of the load (w) that can be applied based on the allowable shear stress of bolts at A,D, C and allowable .normal stress of bars AB, BD, BC
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