00:01
In this equation, it says that the ksp of cobalt hydroxide is 1 .6 times 10 to the exponent 15.
00:07
We need to calculate the solubility for cobalt hydroxide.
00:11
So let's solve it.
00:16
So we can say that our ksp is giving us 1 .6 times 10 to the exponent negative 15.
00:27
So we can say that our cobalt hydroxide cooh -2 will undergo dissociation to produce co2 +, plus 2 moles of oh-.
00:48
So we can say that our ksp will be equal to the concentration of our co2 +, and then the concentration of 2 moles of our hydroxide ion, exponent 2.
01:10
So our ksp will be equal to the concentration of co2 +, and then 2 moles of hydroxide ion, exponent 2.
01:28
And therefore, let's represent our cobalt 2 +, and then our hydroxide ion as x.
01:34
So we have our ksp will be equal to our cobalt 2 +, which is x, and then our hydroxide ion, which is also represented as x.
01:48
So we have 2x, exponent 2...