00:01
So here we're given information about a specific compound.
00:03
We have vanadium 3 hydroxide, which dissociates into vanadium 3 plus and 3 hydroxide anions.
00:11
So let's first solve this without accounting for the auto -ironization of water.
00:16
And the ksp is given as 4 times 10 to the negative 35 retrieved from any table.
00:20
So the solubility is a certain amount of solid that dissolves, increasing the concentration of vanadium and hydroxide.
00:27
So this is equivalent to 27 times the solubility of the fourth path.
00:31
Power, and as a result, we find that the solubility is 1 .0 times 10 to negative 9 molars.
00:39
So seeing if we don't account for the auto ionization of water, this value makes no sense, since if we use the solubility to find the concentration of hydroxide, and we use that to find our ph, we'll essentially find that the ph is essentially less than 7.
00:58
But that makes no sense in this case since we're using a basic hydroxide that produces hydroxide anions in solution.
01:06
So the ph must be greater than 7.
01:09
So the key point to notice here is we can't assume that there's no hydroxide anions in solution.
01:16
So we have to assume that we initially have a concentration of hydroxide initial that is equivalent to 10 to the negative 7 molars...