Question

What is the molarity of a solution of sodium hydroxide, $\mathrm{NaOH}$, if $41.4 \mathrm{~mL}$ of this solution is required to react with $37.5 \mathrm{~mL}$ of $0.0342 \mathrm{M}$ nitric acid solution according to the following reaction? $$ \mathrm{HNO}_{3}+\mathrm{NaOH} \longrightarrow \mathrm{NaNO}_{3}+\mathrm{H}_{2} \mathrm{O}(\ell) $$

          What is the molarity of a solution of sodium hydroxide, $\mathrm{NaOH}$, if $41.4 \mathrm{~mL}$ of this solution is required to react with $37.5 \mathrm{~mL}$ of $0.0342 \mathrm{M}$ nitric acid solution according to the following reaction?
$$
\mathrm{HNO}_{3}+\mathrm{NaOH} \longrightarrow \mathrm{NaNO}_{3}+\mathrm{H}_{2} \mathrm{O}(\ell)
$$

Added by Marcus S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

10/19/2022

Step 1

Given volume of $HNO_3$ solution = 37.5 mL Molarity of $HNO_3$ solution = 0.0342 M Number of moles of $HNO_3$ = Molarity x Volume (L) Number of moles of $HNO_3$ = 0.0342 mol/L x (37.5 mL / 1000 mL/L) = 0.0012825 mol ** Show more…

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What is the molarity of a solution of sodium hydroxide, $\mathrm{NaOH}$, if $41.4 \mathrm{~mL}$ of this solution is required to react with $37.5 \mathrm{~mL}$ of $0.0342 \mathrm{M}$ nitric acid solution according to the following reaction? $$ \mathrm{HNO}_{3}+\mathrm{NaOH} \longrightarrow \mathrm{NaNO}_{3}+\mathrm{H}_{2} \mathrm{O}(\ell) $$