What is the molarity of a sucrose solution that contains 17.0 g of C12H22O11 (342.34 g/mol) dissolved in 122.0 mL of solution? Show work step-by-step and circle or bold answer.
Added by Daniel R.
Step 1
0 g. Given: Mass of sucrose = 17.0 g Molar mass of sucrose (C12H22O11) = 342.34 g/mol Number of moles = Mass / Molar mass Number of moles = 17.0 g / 342.34 g/mol Number of moles = 0.0497 mol Show more…
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