What is the molarity of acetic acid in vinegar that contains 5.00 g of acetic acid (molar mass 60.05 g/mol) in 100. mL of solution?
Added by Robert V.
Step 1
First, we need to find the moles of acetic acid in the solution. To do this, we'll use the given mass of acetic acid and its molar mass: moles of acetic acid = (mass of acetic acid) / (molar mass of acetic acid) moles of acetic acid = (5.00 g) / (60.05 g/mol) Show more…
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Calculate the molarity of acetic acid in vinegar. The vinegar is 5% acetic acid
Bridger J.
For a solution of acetic acid $\left(\mathrm{CH}_{3} \mathrm{COOH}\right)$ to be called "vinegar" it must contain $5.00 \%$ acetic acid by mass. If a vinegar is made up only of acetic acid and water, what is the molarity of acetic acid in the vinegar? The density of vinegar is $1.006 \mathrm{~g} / \mathrm{mL}$.
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