What is the molarity of an HBr solution if 35.8 mL of a 0.180 M Ba(OH)2 solution is required to neutralize a 22.2-mL sample of the HBr solution? 0.223 M 0.145 M 0.290 M 0.112 M 0.581 M
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Given: Volume (V1) = 35.8 mL Molarity (M1) = 0.180 M N factor = 2 (as there are 2 hydroxide ions in Ba(OH)2) Normality (N1) = N factor * Molarity N1 = 2 * 0.180 N1 = 0.360 N Show more…
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