00:01
In this particular question we are told that we are told to calculate the molecular formula of a compound if 0 .50 mole of the compound contains 0 .50mol of strenum 1 .81 times 10xpar 24 heart atoms of oxygen and 35 .5 grams of chlorine.
00:50
So this might look a little bit absorbed to you at first because you're sort of calculate to determine what the molecular formula of the compound is and you're given all this.
01:06
That doesn't even look alike and you don't know where to start from.
01:10
But one thing to know is that well, your compound contains strontium, it contains oxygen, and it contains chlorine.
01:19
But you just don't know in what ratio to one another they are present in the compound.
01:28
Well, you're given this number of mold of strontium and you're given this number of atoms of oxygen.
01:37
And you are given this mass of chlorine.
01:40
So all you have to do is just to combat them to similar units, which in this case will be more high due to have them as 0 .4 as small, because it's easier to work with more.
01:57
All right, so according to havogados law, one more, this is already more, so one more of a compound, contains 6 .02 10 10 to 10s about 23 atoms, right? therefore, 1 .81 times 10 % 24 atoms of oxygen would be equivalent to how many more.
02:35
So that will be 1 .8 .1 times 10 % to par 24 divided by 6 .02 times 10 % to par 23.
02:46
So that will be three moles of oxygen...