What is the momentum and de-Broglie wavelenght of an electron with kinetic energy 120eV.
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Given kinetic energy = 120 eV 1 eV = 1.6 x 10^-19 J Therefore, kinetic energy = 120 x 1.6 x 10^-19 J = 1.92 x 10^-17 J Show more…
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