00:01
Students welcome here in this question for there are three questions are given so three questions are what is the net charge of net charge we have to find out at ph is equal to 7 .2 for a is glutomic acid and b is lysine and c is given glycine for these three, we have to calculate the net charge at ph is equal to 7 .2.
00:40
So we can see here if any group.
00:44
So ph is a greater than pca value, then it is deprotonated.
00:53
Deprotonated form.
00:56
And ph is less than pka, then it is a protonated form.
01:01
Is equal to pca, then it is both forms are exist.
01:11
Both are exist.
01:15
So we will see some information also given pca values of all the groups.
01:22
R group, c -o -h group is given and plus c -o -n -3 plus group also given here.
01:33
The pca values.
01:37
So first for glutamic acid we will see.
01:41
First glutamic acid.
01:46
For pca for our c -o -o -h group is given as 2 .19 is given.
01:55
So this one is p -ka is a ph is greater than p -ka we know that.
02:02
So this is in deep -rated form.
02:05
Deep -e -e -e -l -a form.
02:06
Deep proteinated means the net charge is minus minus 1 and for nh3 we will see so our nh3 group pka is given pka is 9 .67 is given so ph is 7 .2 so pkha is 7 .2 so pka is greater than ph is less than pka so here the this one is protonated form so protonated means the net charge is plus 1.
02:41
Okay.
02:42
Now r group.
02:44
So r group is 0 .25.
02:48
So it is less than ph.
02:50
So ph is greater than pca...