What is the net electric force on charge b in figure 1...

What is the net electric force on charge B in (Figure 1)? Suppose that $a = 1.7 \, cm$ and $b = 1.4 \, cm$. Express your answer to two significant figures and include the appropriate units. Enter negative value if the force is directed downward and positive value if the force is directed upward. A + 1.0 nC B -2.0 nC C +2.0 nC

Transcript

00:01 In this question we have to find the net electric force on charge b and we are given a figure and the value of a is equal to 2 .0 centimeter and we are given the value of b is equal to 1 .3 centimeter.

00:15 So let us see the diagram.

00:18 So this is the diagram over here.

00:20 Now we have to find the net force on charge b.

00:23 So force due to a point charge is given by f is equal to k multiplied by 4.

00:31 Q1, q2 over r square where q1 and q2 are the two charges and r is the distance between them.

00:41 So here the a is a positive charge and b is a negative charge.

00:45 So it will attract each other and c is a positive charge and b is a negative charge so it will also attract each other but since the magnitude of charge c is greater than charge a and the distance will also less its magnitude will be higher so the resultant net force will be towards the downward direction so let us find the net force here net force is equal to so this force will be higher so force due to two my two nanoculum on b is equal to k multiplied by q1 q3 that is two multiplied by two multiplied by multiplied by 10 to the power minus 18 to convert it into coulum over the distance b b is 1 .3 centimeter so it will be 0 .013 square minus because it will act in a positive direction minus charge due to a is k multiplied by the first is one nanoculum other is second second is two nanoculum multiplied 10 to the power minus 18 over the distance 2 cm so it is 0 .0 to whole square now we solve it so we have k multiply by 10 to the plus 18 we will take common and we will take common 2 so we have here it will be 2 k and 10 to 2 minus 18 is common so we are left with 2 over 0 .013 whole square minus k 2 and 10 to 2 minus 18 is outside so we have here 1 over 0 .02 whole square...

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