00:01
Hi, so for this problem first of all let's calculate the pka of our acid.
00:09
This remember is minus the logarithm of the acidic constant so this is minus the logarithm of 5 .6 times 10 to the minus 10.
00:21
The pka it is going to be of 9 .25.
00:37
Okay so now the next step is calculating the ph for the solution of the buffer.
00:42
For buffer solutions what we have is to employ the henderson -hasselbalch equation.
00:48
Ph is equal to pka plus the logarithm of the concentration of the conjugate base divided by the concentration of the acid.
01:03
In order to know those concentrations first of all we want to know the concentration of nh4 plus.
01:15
This is going to be the amount of mole of nh4 plus divided by the final volume.
01:24
In order to know the amount of mole that you added at the beginning you use 0 .1 liters of 0 .2 molar solution and the final volume that we're going to have is 100 milliliters or 0 .1 liters plus 0 .2 liters from the two solutions that we're using.
01:51
So divided by 0 .3 liters.
01:55
Okay so the value for our concentration of nh4 plus it is going to be 6 .66 times 10 to the minus 2 and periodic...