00:01
In this question we have to find out the molarity of nh3, original molarity of the nh3 in one solution we have to find out.
00:12
To find out this one, they given the value of ph of this acquist ammonia solution is 11 .42.
00:22
And the kb, dissociation constant of base, kb is also given.
00:27
That is 1 .8 into 10 to the power 1 .8 multiplied by 10 to the power of minus 5.
00:38
So for this one what i'm going to do means here nh3 is a base.
00:45
For base we have to discuss with the value of p o h but p h is given.
00:50
We know that ph plus p o h is always equal to 14.
00:57
Then p -o -h is equal to 14 minus 11 .42.
01:06
That is equal to it can get 2 .5h.
01:11
So we know that o -h minus concentration is equal to 10 to the power of minus p -o -h.
01:23
That is equal to 10 to the power of minus 2.
01:26
0 .5 which can be written as 10 to the power of minus 3 plus 0 .42...