Question

#include <iostream> using namespace std; int a = 0; int b = 0; void g() { cout << a << " " << b << endl; } int f(int a) { b = 3; g(); { int b = 2; a = 1; g(); } return a + b; } int main() { int a = 4; g(); b = 1; b = f(b); g(); return 0; }

          #include <iostream>
using namespace std;
int a = 0;
int b = 0;
void g()
{
cout << a << " " << b << endl;
}
int f(int a)
{
b = 3;
g();
{
int b = 2;
a = 1;
g();
}
return a + b;
}
int main()
{
int a = 4;
g();
b = 1;
b = f(b);
g();
return 0;
}

#include <iostream>
using namespace std;
int a = 0;
int b = 0;
void g()

cout << a << " " << b << endl;

int f(int a)

b = 3;
g();

int b = 2;
a = 1;
g();

return a + b;

int main()

int a = 4;
g();
b = 1;
b = f(b);
g();
return 0;

Added by Allison L.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Vaibhav Jain

Step 1

The main function is called. Show more…

Show all steps

Thanks for your feedback!

What is the output of the below code while using Dynamic scoping? Please don't send with just compiling and running this program as C/C++ use static scoping. #include <iostream> using namespace std; int a = 0; int b = 0; void g() { cout << endl; } int f(int a) { a = 3; g(); int b = 2; a = 1; g(); return b; } int main() { g(); b = 1; b = f(b); g(); return 0; }