Question

What is the percentage strength of alcohol in a mixture of 500 mL of a solution containing 40% v/v alcohol, 400 mL of a second solution containing 21% v/v alcohol, and a sufficient quantity of a non-alcoholic third solution to make a total of 1000 mL? 28.4% 31.5% 20.3% 33.81%

          What is the percentage strength of alcohol in a mixture of 500 mL of a solution containing 40% v/v alcohol, 400 mL of a second solution containing 21% v/v alcohol, and a sufficient quantity of a non-alcoholic third solution to make a total of 1000 mL?

28.4%
31.5%
20.3%
33.81%

What is the percentage strength of alcohol in a mixture of 500 mL of a solution containing 40% v/v alcohol, 400 mL of a second solution containing 21% v/v alcohol, and a sufficient quantity of a non-alcoholic third solution to make a total of 1000 mL?

28.4%
31.5%
20.3%
33.81%

Added by Christopher H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Chareen Guzman

11/01/2023

Step 1

For the 500 mL of the first solution containing 40% vlv alcohol: Alcohol content = 500 mL x 0.40 = 200 mL For the 400 mL of the second solution containing 21% vlv alcohol: Alcohol content = 400 mL x 0.21 = 84 mL So the total amount of alcohol in the Show more…

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What is the percentage strength of alcohol in a mixture of 500 mL of a solution containing 40% v/v alcohol, 400 mL of a second solution containing 21% v/v alcohol, and a sufficient quantity of a non-alcoholic third solution to make a total of 1000 mL? 28.4% 31.5% 20.3% 33.81%