00:01
In stoichiometry, we relate the quantities of the substances that are involved in a chemical reaction.
00:07
Here we have the reaction between hbr and koh to form kbr salt and h2o according to this balanced equation.
00:17
If we have 25 ml of 1 molar of the acid reacting with 20 ml of the same concentration of the base, then we want to find the ph of the resulting solution.
00:41
So we first compute for the minimals of each reactant.
00:46
So let's say for the acid first, so to find the minimals, we just have to multiply the molarity by the ml.
00:53
So we have 25 times 1 giving us 25.
00:58
We do the same for the base.
01:01
We have 1 times the molarity times 20, that's 20.
01:06
So from the balanced equation, we find that for every 1 mol of hbr, 1 mol of the koh also reacts.
01:15
So that all of the koh here as it comes in lesser amount will be consumed and some of the hbr will be left at the reaction...