00:01
Hello students, in this question basically a morphine solution is given.
00:04
We know that the morphine is a type of the base or we can say that weak base here the value of kb that is the ionization constant for base is given that is 1 .6 into 10 to the power minus 6 and concentration of morphine is given that is the base that is given which is the 0 .0075 molar and we know that morphine is a type of the weak base.
00:33
So kb here should be the bh plus into oh minus divided by b and we have the values of the let's say the value of the bh plus is equal to oh minus this should be equal to x and the value of b should be that is morphine should be equal to the 0 .0075 minus x here.
01:03
So put the value of the kb and this bh plus oh minus and b in this equation and kb here is the 1 .6 into 10 to the power minus 6 and this is x into x divided by the 0 .0075 minus x as we know that the let's say assume the 0 .0075 is greater than x.
01:29
So x can be neglected here.
01:37
So 1 .6 into 10 to the power minus 6 should be equal to x square divided by 0 .0075 as you know that if we calculate this from this the value of x should be equal to the under root of 1 .6 into 10 to the power minus 6 into 0 .0075.
01:59
So this should be equal to the 0 .00137 molar as we know that here we have calculated the x is the concentration of oh minus as we know we assume it.
02:12
So this is equal to the 0 .00137 molar here we can easily calculate the poh because poh should be equal to the minus log of oh minus.
02:25
So here we can easily calculate the poh.
02:28
So poh should be equal to the minus log of 0 .00137...