What is the pH of a 0.880 M solution of \( \mathrm{Ca}\left(\mathrm{NO}_{2}\right)_{2}\left(\mathrm{Ka}\right. \) of \( \mathrm{HNO}_{2} \) is \( 4.5 \times \) \( \left.10^{-4}\right) \) ?
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In solution, it dissociates into \( \text{Ca}^{2+} \) and \( \text{NO}_2^- \). Show more…
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