What is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka = 6.8 × 10??) and 0.200 mol of NaF to which 0.080 mol of NaOH were added?
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First, we need to find the initial concentrations of HF and F- before adding NaOH. Initial concentration of HF = moles of HF / volume of buffer = 0.300 mol / 1.0 L = 0.300 M Initial concentration of F- = moles of NaF / volume of buffer = 0.200 mol / 1.0 L = Show more…
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