00:01
The question says to find the ph of nh4 cl.
00:06
The ph of nh4.
00:09
You have to find its ph.
00:11
And what is given here? the concentration is given here which is equal to 3 .6 molar.
00:18
And what is given here? the value of kv for nh3.
00:21
This is given here which is equal to 1 .78 multiplied by 10 power minus 5.
00:28
So let's see the explanation for it.
00:36
So first of all, if we talk for nh4c4.
00:40
This nh4 came from a weak base from naoh and this scl came from a strong acid that is from scl.
00:53
So we can say that nh4 cl is a salt of weak base and strong acid.
01:07
So what we can say the resultant solution here will be acidic.
01:13
The resultant solution here is acidic.
01:22
This is really important.
01:23
And acetic means the ph will be less than 7.
01:27
This is confirmed from here that ph will be less than 7.
01:30
Now if we see that we have given the value of kb which is equal to 1 .78 multiply by 10 power minus 5.
01:40
There is a formula which is ka multiplied by kab whose total value is 10 power minus 14.
01:48
From here we can calculate the value of ka as the value of kb is given.
01:53
So ka multiply by 1 .78 multiplied by 10 power minus 5 is given as 10 power minus 14.
02:00
From here we can calculate the value of ka, the value of ka, the value of ka .r.
02:09
Now if we see for nh4 positive ion hydrolysis, so i will write here for 4, for the value of 10, for n h positive ion hydrolysis what will be the equation here the equation will be nh4 positive plus h2 o this will give n h3 plus s3 o positive as we know that the value of kb is given for n s 3 here now what will be the formula for k a k a will be equal to n h3 concentration multiply by concentration of h3 of positive divided by the concentration of n h positive here.
02:54
We will not take h2o as h2 is a pure liquid...