What is the pH of a buffer that results when 5.70 moles of H3PO4 is mixed with 4.96 moles of NaOH and diluted with water to 1.00 L? (The acid dissociation constants of phosphoric acid are Ka1 = 7.5 × 10–3, Ka2 = 6.2 × 10–8, and Ka3 = 3.6 × 10–13)
Added by Noelia S.
Step 1
Given: Moles of H3PO4 initially = 5.70 moles Moles of NaOH added = 4.96 moles Moles of H3PO4 remaining = 5.70 moles - 4.96 moles Moles of H3PO4 remaining = 0.74 moles Show more…
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