1. What is the pH of a solution after 10.0mL of 0.20 M LiOH has been added to 50.0mL of 0.10 M HOCl. pKa = 7.54.
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Moles of LiOH = (0.20 mol/L) * (10.0 mL / 1000 mL) = 0.002 mol Moles of HOCl = (0.10 mol/L) * (50.0 mL / 1000 mL) = 0.005 mol Show more…
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