What is the pressure in atm of a 4.00 L container containing 1.00 atm of O2 and 1420 mmHg of N2?
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We know that 1 atm = 760 mmHg. So, we can convert 1420 mmHg to atm by dividing by 760: 1420 mmHg / 760 mmHg/atm = 1.8684 atm Now, we have 1.00 atm of O2 and 1.8684 atm of N2 in the container. Show more…
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