What is the pressure inside a bubble of soap solution of radius 5 mm , given that the surface tension of soap solution at temperature (20c) is 2.5*10^-2 N/m? density of the soap bubble = 1.20 kg/m^3
Added by Yash G.
Step 1
Given: Surface tension, S = 2.5 x 10^-2 N/m Radius, R = 5 x 10^-3 m Plugging in the values: P = 2 * 2.5 x 10^-2 / 5 x 10^-3 P = 20 Pa Show more…
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What is the excess pressure inside a bubble of soap solution of radius $5.00 \mathrm{~mm}$ ? Given that the surface tension of soap solution at the temperature $20^{\circ} \mathrm{C}$ is $2.50 \times 10^{-2} \mathrm{~N} / \mathrm{m}$. If an air bubble of the same dimension were formed at a depth of $40.0 \mathrm{~cm}$ inside a container containing the soap solution (of relative density $1.20$ ), what would be the pressure inside the bubble? $\left(1 \mathrm{~atm}=1.01 \times 10^{5} \mathrm{~Pa}\right)$
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Section F
What is the excess pressure inside a bubble of soap solution of radius $5.00 \mathrm{~mm}$, given that the surface tension of soap solution at the temperature $\left(20^{\circ} \mathrm{C}\right)$ is $2.50 \times$ $10^{-2} \mathrm{~N} \mathrm{~m}^{-1} ?$ If an air bubble of the same dimension were formed at depth of $40.0$ $\mathrm{cm}$ inside a container containing the soap solution (of relative density $1.20$ ), what would be the pressure inside the bubble? (1 atmospheric pressure is $1.01 \times 10^{5} \mathrm{~Pa}$ ).
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