What is the repulsive force between two pith balls that are 8.00 $\mathrm{cm}$ apart and have equal charges of $-30.0 \mathrm{nC}$ ?
Added by Peter B.
Step 1
0 nC, we have: Q1 = Q2 = -30.0 nC = -30.0 x 10^-9 C Show more…
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