(a) What is the resistance (in ?) of a 230 V AC short circuit that generates a peak power of 96.9 kW? ? (b) What would the average power (in kW) be if the voltage was 120 V AC? kW
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We know that the peak power (P_peak) is 96.9 kW and the voltage (V) is 230 V AC. We can use the formula: P_peak = V * I_peak Now, we can solve for I_peak: I_peak = P_peak / V I_peak = 96900 W / 230 V I_peak ≈ 421.74 A Show more…
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